Under normal circumstances, the recommended fertilization rates for the formula fertilization test are pure nitrogen, P2O5 (phosphorus pentoxide), and K2O (potassium oxide). However, due to the different effective content of various fertilizers, it is not easy for farmers to accurately grasp the amount of fertilizer used in the actual production process. The following is a simpler way to calculate the amount of fertilizer applied to the soil.
Assume that the amount of fertilizer recommended for this plot is 8.5 kg per gram of pure nitrogen, P2O54.5 kg, and K2O 6.5 kg. Single fertilization. The calculation method is: The effective content of the recommended fertilizer is quantified fertilizer = quantity that should be fertilized. The following results can be obtained: Urea application (urea nitrogen content is generally 46%) is 8.546% = 18.5 (kg).
Applying potassium sulfate (K2O in potassium sulfate is generally 50%) is 6.550% = 13 (kg) application of compound fertilizer. If compound fertilizer is used, the amount should be calculated based on the fertilizer with the least amount of fertilizer recommended on the formula fertilization table, and then the other two kinds of fertilizers should be added. If the content of nitrogen, phosphorus, and potassium marked on a compound fertilizer bag is 15:15:15, the compound fertilizer should be applied on the plot: 4.815%=32 (kg). In this way, the phosphorus in the soil already meets the nutrition needed by the crop. Due to the fixed proportion of compound fertilizers, it is difficult to meet the demand of various nutrients for different crops in different soils at the same time. Therefore, the unit fertilizer needs to be added to supplement, and the formula is: (Recommended fertilizer amount - applied fertilizer amount) Effective content of fertilizer to be applied = Supplemental fertilizer amount. The plot has been applied with 32 kg of compound fertilizer with N, P, and K contents of 15% each, which is equivalent to 3215% of pure nitrogen in the applied soil, and 4.8 kg of P2O5 and K2O. According to the requirements of the recommended fertilization amount of 8.5 kg of pure nitrogen and K2O of 6.5 kg, additional application is required: urea (8.5-4.8) 46% = 8 (kg), potassium sulfate (6.5-4.8) 50% = 3.4 (kg ).
Assume that the amount of fertilizer recommended for this plot is 8.5 kg per gram of pure nitrogen, P2O54.5 kg, and K2O 6.5 kg. Single fertilization. The calculation method is: The effective content of the recommended fertilizer is quantified fertilizer = quantity that should be fertilized. The following results can be obtained: Urea application (urea nitrogen content is generally 46%) is 8.546% = 18.5 (kg).
Applying potassium sulfate (K2O in potassium sulfate is generally 50%) is 6.550% = 13 (kg) application of compound fertilizer. If compound fertilizer is used, the amount should be calculated based on the fertilizer with the least amount of fertilizer recommended on the formula fertilization table, and then the other two kinds of fertilizers should be added. If the content of nitrogen, phosphorus, and potassium marked on a compound fertilizer bag is 15:15:15, the compound fertilizer should be applied on the plot: 4.815%=32 (kg). In this way, the phosphorus in the soil already meets the nutrition needed by the crop. Due to the fixed proportion of compound fertilizers, it is difficult to meet the demand of various nutrients for different crops in different soils at the same time. Therefore, the unit fertilizer needs to be added to supplement, and the formula is: (Recommended fertilizer amount - applied fertilizer amount) Effective content of fertilizer to be applied = Supplemental fertilizer amount. The plot has been applied with 32 kg of compound fertilizer with N, P, and K contents of 15% each, which is equivalent to 3215% of pure nitrogen in the applied soil, and 4.8 kg of P2O5 and K2O. According to the requirements of the recommended fertilization amount of 8.5 kg of pure nitrogen and K2O of 6.5 kg, additional application is required: urea (8.5-4.8) 46% = 8 (kg), potassium sulfate (6.5-4.8) 50% = 3.4 (kg ).
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